Question

2KCIO3— 2KCI +302
How many grams of oxygen are produced by the decomposition of 6.0 moles of potassium chlorate, KCIO3? (Arso
=16, K=39. C1 = 35.5)
Moles of oxygen-
Grams of oxygen =

Answer 1

Explanation:

ANSWER

Decomposition of KClO

3

takes place as:

2KClO

3

(s)→2KCl(s)+3O

2

(g)

2 mole of KClO

3

=3 mole of O

2

∵ 3 mole O

2

formed by 2 mole KClO

3

∴2.4 mole of O

2

will be formed by:

(

3

2

×2.4) mol KClO

3

= 1.6 mole of KClO

3

.

Mass of KClO

3

= Number of moles × Molar mass

=1.6×122.5=196g