Question

2KClO3 →2KCl + 3O2 How many moles of oxygen are produced by the decomposition of eight moles of potassium chlorate?

Answer 1

Answer:

2KClO3 --> 2KCl + 3O2

The balanced equation tells us that we get 3 moles of O2 for every 2 moles of KClO3.

We can form a molar ratio:

(3/2)(moles O2/moles KClO3)

If we start with 3.0 moles KClO3, we'll get

(3/2)(moles O2/moles KClO3)*(3 moles KClO3) =

(3/2)*(3.0) moles O2, or 4.5 mole