Question

2kg are
Two blocks of masses 3 kg and
placed in contact with each other in a
friction less table. find the force on the common
cross-sectional area of contact if a force
of 5 N is applied on
() bigger bloch
(ii smaller block-
م​

Answer 1

Explanation:

Given

F=5N

m1=3kg

m2=2kg

F=ma

F=(m1+m2)a

F=(3+2)a

F=5+3/2a

a=1m/s²

For Bigger Block,

F=ma

F=3×1

F=3N

For Smaller Block,

F=ma

F=2×1

F=2N