2kg bullet fired from a cannon of mass 198 kg with.velocity 50m/switch respect to gun the the recoil velocity
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Mass of bullet m1 = 2 kg
Speed of bullet v1 = 50 m/s
Mass of Cannon m2 = 198 kg
Total momentum of system after collision is zero
m1 v1 + m2v2. = 0
v2 = - m1 v1/ m2
v2 = - 2 × 50 / 198
= - 0 . 50
negative sign show that the gun move opposite to the bullet
therefore recoil velocity is 0.50.
Speed of bullet v1 = 50 m/s
Mass of Cannon m2 = 198 kg
Total momentum of system after collision is zero
m1 v1 + m2v2. = 0
v2 = - m1 v1/ m2
v2 = - 2 × 50 / 198
= - 0 . 50
negative sign show that the gun move opposite to the bullet
therefore recoil velocity is 0.50.
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