Question

2kg of air is heated at constant volume.the temperature of air is increased from 293 k to 313 k. if the specific heatbof air at constant volume is 0.718 kj/kg k the amount of heat absorbed in kj and kcal is (4200/kcal)​

Answer 1

Answer:

Heat absorbed H = m s T

H = 2 kg * 0.718 kJ/ °K/kg * (313-293)°K

H = 28.72 kJ

H = 28.72/4.18 kCal

Explanation:

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