2kg of CaCO3 decomposes completely on heating and forms CaO2. if 880 g ofCO2 is formed, what is mass of CaO formed
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The decomposition of CaCO3 is as follows:
CaCO3(s) ---------> CaO(s) + CO2(g)
The mole ratio of the equation is 1:1:1....this 1 mole of CaCO3 yields 1 mole of CaO and 1 mole of CO2.
Calculate the moles of CaCO3:
moles = mass/molar mass
moles = 5/100
= 0.05 moles
This means that the moles of the CaO produced is also 0.05 moles since the mole ratio is 1:1:1
mass = moles × molar mass
= 0.05 × 56
2.8 grams
Mass of CO2:
mass = moles × molar mass
0.05 × 44
= 2.2 grams of CO2
CaCO3(s) ---------> CaO(s) + CO2(g)
The mole ratio of the equation is 1:1:1....this 1 mole of CaCO3 yields 1 mole of CaO and 1 mole of CO2.
Calculate the moles of CaCO3:
moles = mass/molar mass
moles = 5/100
= 0.05 moles
This means that the moles of the CaO produced is also 0.05 moles since the mole ratio is 1:1:1
mass = moles × molar mass
= 0.05 × 56
2.8 grams
Mass of CO2:
mass = moles × molar mass
0.05 × 44
= 2.2 grams of CO2
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