Question

2kg of water at 0°C is changed into ice at 0°C calculate the amount of heat energy given out in SI units. (specific latent heat of vapourization of steam is 336 kJ/kg)​

Answer 1

Answer:

835.48kJ

Explanation:

Total heat = Heat required to convert 2kg of ice to 2kg of water at  0℃ +Heat required to convert 2kg of water at 0℃ to 2kg of water at 20℃

Heat=mhfg+mCp\Delta t$$

Here, m(mass of ice)=2kg

hfg(latent heat of fusion of ice)=334kJ

Cp of water(specific heat)=4.187 kJ/kg-k

Δt(temperature difference) =20℃

Therefore,

Heat required=2×334+2×4.187×(20−0)

                     =835.48 kJ

Therefore, to melt 2kg of ice 835.48kJ of heat is required.