2KJ of heat energy is produced cacl second in 20 ohm resistor.find the potential difference across the resistor
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2 kJ each second .
so power =P = 2 kW
R = resistance = 20 ohm
V = potential
P = V² / R
so V² = P R = 2000 * 20 = 40000
V = 200 Volts
so power =P = 2 kW
R = resistance = 20 ohm
V = potential
P = V² / R
so V² = P R = 2000 * 20 = 40000
V = 200 Volts
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