Question

2KMnO gives KMnO, + MnO + O Given that the molecular mass of KMnO4 is 158, what
volume of oxygen (measured at room temp.] would be obtained by the complete decomposition of
15 g of potassium permanganate. I Molar volume at room temperature is 24 litres.​

Answer 1

2KMnO4 → K2MnO4 + MnO2 + O2 Given that the molecular mass KMnO4 is 158, what volume of oxygen (measured at room temperature) would be obtained by the complete decomposition of 15.8 g. of potassium permanganate. (Molar volume at room temperature is 24 litres.)Read more on Sarthaks.com - https://www.sarthaks.com/284942/2kmno4-k2mno4-mno2-o2-given-that-the-molecular-mass-kmno4-is-158-what-volume