Math, asked by rehanadabbawala73, 9 hours ago

2kx^2-3kx+k+1=0 roots of the equation is equal find the value of k

Answers

Answered by AarushChd
1

Step-by-step explanation:

Thegivenequationis2kx2+2kx+2=0⇒kx2+kx+1=0Itisoftheformax2+bx+c=0∴a=b=k,c=1.Sincetherootsareequalwehaveb2=4ac.Substitutingthevalueofa,bandcwehavek2=4k⇒k2−4k=0⇒k(k−4)=0∴eitherk=0whichisimpossibleinthiscaseasitiscoefficientofx2intheequation.∴Werejectk=0∴k−4=0⇒k=4(Ans)

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