Question

2L of Hydrogen gas reacts with 1L of oxygen gas to produce--- water vapour​

Answer 1

Answer:

........................m

Answer 2

Answer:

Take the mass of 1.0L of water as 1000g

Molar mass H2O = 18g/mol

Mol H2O in 1000g = 1000g/18g/mol = 55.55 mol H2O

Equation:

2H2 + O2 → 2H2O

2mol H2 reacts with 1 mol O2 to produce 2 mol H2O

55.55 mol H2 reacts with 55.55/2 = 27.775 mol O2 to produce 55.55 mol H2O

What is the volume of H2 and O2 ? Without details of temperature and pressure , impossible to say

But if we work at STP

1 mol H2 and 1 mol O2 each has volume 22.4L

Volume of H2 = 55.55mol * 22.4L/mol = 1,244L

Volume of O2 = 27.775*2204 =622L

Explanation:

In one liter of water there are no liters of hydrogen and oxygen at all. Rather, from 1 liter of water, one can obtain a certain number of liters of gaseous hydrogen and half that number of liters of gaseous oxygen. Actually, 1 liter of water has a mass of about 1000 g, which corresponds to about 55 moles of water. By electrolysis, from 1 mole of water, one obtains one mole of hydrogen and half mole of oxygen. At room temperature and pressure, one mole of any gas corresponds to about 24.5 liters. So, from one liter of liquid water one can obtain about 1.36 cubic meters of molecular hydrogen and 0.68 cubic meters of molecular oxygen.