2l of N2 and 2l of H2 on complete really reaction would give...... litre of NH3
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Answer:
N2 + 3H2= 2NH3
Here, H2 is the limiting reagent so we will use H2 as the subject
3 mole H2 gives 2 mole NH3
(3×22.4)lt H2 gives (2×22.4)lt NH3
1 lt H2 gives (2×22.4)/(3×22.4)lt NH3
=2/3 lt NH3
so, 2 lt H2 gives 2×2/3 lt NH3
=4/3 lt NH3
= 1.33 lt NH3
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