Math, asked by deepak9017, 1 year ago

2log(11/13)+2log(130/33)-log(4/9)

Answers

Answered by manamperi344
12

2log(11/13) + 2log(130/33) - log(4/9)

= 2log(11/13) + 2log(130/33) - log[ (3/2)^(-2) ]  {Use log(a^k) = klog(a) }

= 2log(11/13) + 2log(130/33) + 2log(3/2)

= 2log(11/13 x 130/33 x 3/2) { Use log(a) + log(b) = log(ab) }

= 2log(5)

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