Math, asked by spoorthy8, 11 months ago

(2log 5+log 4^2+3 log 2)-2 = m log 2.so find the value of m

Answers

Answered by dupananani90

1

Answer:

(log25+log16+log8)-2=mlog2

(log25×16×8)-2=mlog2

log3200-2=mlog2

m=log3200-2/log2

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