Question

2log(x+1]=log2+logx then find x

Answer 1

The solution will be like this
2log(x+1)=log(2x)
taking antilog on both sides we get
(x+1)to the power 2 =2x
x to the power 2 +2*x*1 +1 =2x
x to the power 2 +2x+1 =2x
x to the power 2 =2x-2x-1
x to the power 2 = -1
squareing both sides we have
x =1

Answer 2

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