Question

2log(x+3)=log81 find x

Answer 1

log(x+3)^2=log81
=(x+3)^2=81
x^2+9+6x=81
x^2+6x-72=0
x^2+12x-6x-72=0
x(x+12)-6(x+12)=0
(x+12)(x-6)=0
x=6,-12
is your answer

Answer 2

$2log (x + 3) = log81 \\ = > 2log(x + 3) =log {9}^{2} \\ = > 2log(x + 3) = 2log9 \\ = > x + 3 = 9 \\ = > x = 9 - 3 = 6$
HOPE THIS HELPS YOU!!!