2log x / log(5x-4)= 1
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Answer:
x = 4
Note:
★ log(A•B) = logA + logB
★ log(A/B) = logA - logB
★ logAⁿ = n(logA)
★ log1 = 0
★ logA = logB => A = B
Solution:
We have ;
=> 2logx / log(5x - 4) = 1
=> 2logx = log(5x - 4)
=> logx² = log(5x - 4)
=> x² = 5x - 4
=> x² - 5x + 4 = 0
=> x² - 4x - x + 4 = 0
=> x(x - 4) - (x - 4) = 0
=> (x - 4)(x - 1) = 0
=> x = 1 , 4
Also,
At x = 1
log(5x - 4) = log(5×1 - 4)
= log(5 - 4)
= log1
= 0
Here ,
x = 1 is rejected value , because at x = 1 the value of log(5x - 4) is 0 which is not possible to have in denominator .
Thus,
The appropriate value of x is 4 .
Hence,
x = 4
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