Question

2log(x-y/2)=log x + log y +log 3 find the value of x/y+y/x​

Answer 1

Answer:

Step-by-step explanation:

2log(x-y/2)=logxyz (∵logx +logy+logz=logxyz)

log(x-y/2)∧2=logxyz (∵2logx=logx∧2)

cancel the log from both sides

(x-y/2)∧2=xyz

(x-y)∧2/4=xyz

x∧2+y∧2+2xy=4xyz

divide by xy

x/y+y/x+2=4z

x/y+y/x=4z-2