Math, asked by eashumanu, 7 months ago

2log3√3+3log2-log20-1 as single logarithm​

Answers

Answered by sunit0333
6

log7/25

Step-by-step explanation:

= 2log3√3 + 3log2 - log20 -1

= log(3√3)^2 + log(2)^3 - log20 - log 10

= log[{(3√3)^2*(2)^3}÷(20*10)}]

= log{(27*8)÷200}

= log(56÷200)

= log(7/25)

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