Question

2log5+1/2log9-log3=logx find c

Answer 1

Step-by-step explanation:

The given equation is

2\log 5+\frac{1}{2}\log 9-\log 3 =\log x2log5+

2

1

log9−log3=logx

We need to find the value of x.

Using power property of logarithm, the given equation can be rewritten as

\log 5^2+\log 9^{\frac{1}{2}}-\log 3 =\log xlog5

2

+log9

2

1

−log3=logx [\because \log_a x^n=n\log_a x][∵log

a

x

n

=nlog

a

x]

\log 25+\log 3-\log 3 =\log xlog25+log3−log3=logx

\log 25 =\log xlog25=logx

On comparing both sides we get

x=25x=25

Answer 2

answer:

explaination:

• value of x is 25