Question

2log5+log3+3log2-1/2log36-2log10 ​

Answer 1

Solution :

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We know the logarithmic laws :

i ) n log m = log mⁿ

ii ) log m + log n = log mn

iii ) log m - log n = log ( m/n )

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2log5 +log 3+3log2-1/2 log 36-2log10

= log5² + log 3 + log 2³- log√36-log10²

= log 25 + log3 + log 8 - log 6 - log 100

= log ( 25 × 3 × 8 ) - ( log 6 + log 100 )

= log 600 - log 600

= 0

Answer 2

the answer given above is right