Question

2log5+log3+3log2-1/2log36-2log10
Please solve this fast

Answer 1

Answer:

$2log5+log3+3log2-\frac{1}{2}log36-2log10=log\left(\frac{\frac{\left(5^2\cdot 3\cdot 2^3\right)}{36^{\frac{1}{2}}}}{10^2}\right)=log\left(\frac{\frac{600}{6}}{100}\right)=log\left(\frac{100}{100}\right)=log1=0$

Hope this helps :)

Step-by-step explanation:

Answer 2

Solution :

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We know the logarithmic laws :

i ) n log m = log mⁿ

ii ) log m + log n = log mn

iii ) log m - log n = log ( m/n )

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2log5 +log 3+3log2-1/2 log 36-2log10

= log5² + log 3 + log 2³- log√36-log10²

= log 25 + log3 + log 8 - log 6 - log 100

= log ( 25 × 3 × 8 ) - ( log 6 + log 100 )

= log 600 - log 600

= 0

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