Question

2log7/9-4log2/3+3log4/7=2log-log7​

Answer 1

Step-by-step explanation:

log(a/b)=loga - log b

2log7/9=2×(log7-log9)

=2×(log7-log3^2)

=2×(log7-2log3)

=2log7-4log3--A

4log2/3=4×(log2-log3)

=4log2-4log3 --B

3log 4/7=3×(log 4- log 7)

=3×(log2^2-log7)

=3×(2log2 -log7)

=6log2-3log7 ---C

A-B+C

=2log7-4log3-4log2+4log3+6log2-3log7

=2log2-log7

hope this helps

Answer 2

don't know what to write