2logbase10 5log base 10 8- 1/2 log base 10 4 solve this q
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Answered by
98
Hi ,
*****************
Here we use following laws:
1 ) log m + log n = log mn
2 ) log m - log n = log ( m/n )
3 ) m log n = log n^m
4 ) log ( base x ) x = 1
****************
2 log ( base 10 ) 5 + log ( base 10 ) 8 -
1/2 log ( base 10 ) 4
= 2log 5 + log 8 - 1/2 log 4
= log 5² + log 8 - log √4
= log 25 + log 8 - log √2²
= log ( 25 × 8 ) - log 2
= log 200/2
= log 100
= log 10²
= 2log ( base10 )10
= 2
I hope this helps you.
:)
*****************
Here we use following laws:
1 ) log m + log n = log mn
2 ) log m - log n = log ( m/n )
3 ) m log n = log n^m
4 ) log ( base x ) x = 1
****************
2 log ( base 10 ) 5 + log ( base 10 ) 8 -
1/2 log ( base 10 ) 4
= 2log 5 + log 8 - 1/2 log 4
= log 5² + log 8 - log √4
= log 25 + log 8 - log √2²
= log ( 25 × 8 ) - log 2
= log 200/2
= log 100
= log 10²
= 2log ( base10 )10
= 2
I hope this helps you.
:)
Answered by
34
hope this helps you...... use the laws
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