Question

2logx+ logy = log(x+y) then y is?
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Answer 1

Answer:

$2log( {x} ) + log(y) = log(x + y) \\ \\ log( {x}^{2} ) + log(y) = log(x + y) \\ \\ log( {x}^{2} \times y) = log(x + y) \\ \\ {x}^{2} \times y = x + y \\ \\ x + y - {x}^{2} y = 0 \\ \\ y(1 - {x}^{2} ) = - x \\ y = \frac{ - x}{1 - {x}^{2} }$

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