[ 2m+ 1/4] [2m+1/4] dove this question
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Answer:4m²+1m+1/16²
Step-by-step:
= (2m+1/4)²
= (a+b)²=a²+2ab+b²
= ( 2m)²+2×2m×1/4+(1/4)²
= 4m²+1m+1/16².
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Answer:
Consider the equation: x4−(2m−1)x2+4m−5=0 with m∈R. I have to find the values of m such that the given equation has all of its roots real. .
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