Question

(2m-1)+(m-1)= m+2 the root of the equation​

Answer 1

Answer:

Given that:

mx

2

+(2m−1)x+(m−2)=0 where m is an integer.

To find:

m=?

Solution:

Discriminant,D=b

2

−4ac

or, D=(2m−1)

2

−4m(m−2)

or, D=4m

2

+1−4m−4m

2

+8m

or, D=4m+1

For a rational root, D must be a square.

Since value of D is odd number,

So D=4m+1 can be represented as

Let 2n+1 is an odd number

or, (2n+1)

2

=4n

2

+4n+1

=4n(n+1)+1

So integral value of n is n(n+1).

Hence, C is the correct answer.

Answer 2

Answer:

(2m-1)+(m-1)=m+2

2m-1+m-1=m+2

2m+m-1-1=m+2

3m-2=m+2

3m-m=2+2

2m=4

m=4÷2

m=2

Answer...2