Question

(2m+1)x^2+2(m+3)x+(m+5)=0 find value of m having equal roots explain with step by step​

Answer 1

Answer:

This quadratic equation will have equal roots when the discriminant(b^2 - 4ac) is equal to 0

therefore

(2*(m+3))^2 -4*(2m+1)*(m+5) = 0

therefore 4(m^2 + 9 + 6m) - 4(2m^2 +11m + 5) = 0

which is (-m^2 -5m +4) = 0

therefore we can write it as m^2 + 5m - 4  = 0

therefore on solving the quadratic formula

m = (-5 +/- $\sqrt{b^2-4ac}$)/2a

therefore roots are

m1:0.7015

m2:-5.7015

Step-by-step explanation: