Math, asked by iamme88, 2 months ago

(2m)^2+(m^2-1)^2=(m^2+1)^2​

Answers

Answered by shivrajyashwantpatil
0

Answer:

4m^2+m^2-1 = m^2+1

hope you understand it

Answered by namankamra2005
0

Answer:

Step-by-step explanation:

LHS=

(2m)^2+(m^2-1)^2=

4m^2+(m^4-2m^2+1)=

m^4+2m^2+1

=(m^4+2*m^2*1+1^2)

=(m^2+1)^2

=RHS

hence proved

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