(2m)^2+(m^2-1)^2=(m^2+1)^2
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Answered by
0
Answer:
4m^2+m^2-1 = m^2+1
hope you understand it
Answered by
0
Answer:
Step-by-step explanation:
LHS=
(2m)^2+(m^2-1)^2=
4m^2+(m^4-2m^2+1)=
m^4+2m^2+1
=(m^4+2*m^2*1+1^2)
=(m^2+1)^2
=RHS
hence proved
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