Math, asked by amrithpradeep2007, 6 days ago

(2m - 3/2 × n)^3
(x - y)  ^{3}  = x ^{3}  - y ^{3}  - 3x ^{2} y + 3xy ^{2}

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Answered by pantjyoti101
1

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Answered by abhayanand42173
0

Answer:

(x+y)3=x3+y3+3x2y+3xy2

L.H.S. =(x+y)3=[2+(−3)]3=(2−3)3

=(−1)3=(−1)×(−1)×(−1)=−1

R.H.S. =x3+y3+3x2y+3xy2

=(2)3+(−3)3+3(2)2(−3)+3×2(−3)2

=8−27+3×4×(−3)+6(9)

8−27−36+54=62−63=−1

∴L.H.S=R.H.S

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