2m+3n) + (2m-3n)3 + 12m (4m² - 9n) with this formula a³+b³+3ab(a+b)
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20
0
-40
20
09) 50 °C = ___°R
1 point
40
20
50
30
04) A faulty thermometer has its fixed points marked as 5 and 95. If the temperature of the body as shown on Celsius scale is 40 then the temperature shown by faulty thermometer is
1 point
36
31
46
41
Step-by-step explanation:
20
0
-40
20
09) 50 °C = ___°R
1 point
40
20
50
30
04) A faulty thermometer has its fixed points marked as 5 and 95. If the temperature of the body as shown on Celsius scale is 40 then the temperature shown by faulty thermometer is
1 point
36
31
46
41
Answered by
1
Answer:
Step-by-step explanation:
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