Math, asked by akankshanareti52, 11 months ago

(2m-8n)2+(2m+8n)2 simplify​


mokshita412: (2m-8n)2+(2m+8n)2=4m-16n+4m+16n=8m
Shahoodalam: hmmmmm

Answers

Answered by NeelamG
46

(2m-8n)²+(2m+8n)²

= 4m²+64n²-32mn+4m²+64n²+32mn

= 8m²+128n²

= 8(m² + 16n²)


akankshanareti52: yes 2in power
Shahoodalam: ok
Shahoodalam: you checked in book
Shahoodalam: then what is your answer in book
NeelamG: if 2 in power my solution is correct i hope it will help u
akankshanareti52: this is a assignment question
Shahoodalam: do you know about power
NeelamG: okk
Shahoodalam: can you post pic
Shahoodalam: of your assignment
Answered by pulakmath007
4

(2m - 8n)² + (2m + 8n)² = 8m² + 128

Given :

The expression (2m - 8n)² + (2m + 8n)²

To find :

Simplify the given expression

Formula :

  • (a + b)² = a² + 2ab + b²

  • (a - b)² = a² - 2ab + b²

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is (2m - 8n)² + (2m + 8n)²

Step 2 of 2 :

Simplify the given expression

We use the formula

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

Thus we get

  \sf  {(2m - 8n)}^{2}  + {(2m  +  8n)}^{2}

  \sf   =  \{ {(2m)}^{2} - 2 \times 2m \times 8n +  {(8n)}^{2}   \}  + \{ {(2m)}^{2}  + 2 \times 2m \times 8n +  {(8n)}^{2}   \}

  \sf   =  (4 {m}^{2}  - 32mn + 64 {n}^{2} ) + (4 {m}^{2}   + 32mn + 64 {n}^{2} )

  \sf   =  8 {m}^{2}   + 128 {n}^{2}

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