Math, asked by poojakakkad235, 1 year ago

(2m),(m-1) is a solution of 2x+3y-9=0, find the value of m

Answers

Answered by Anonymous
2

Answer:


Step-by-step explanation:

Let x=2m

And y=m-1

So

2x+3y-9=0

2x+3y=9

2×2m+3×(m-1)=9

4m+3m-3=9

7m=9+3

7m=12

m=12/7

Hope it helps u✌✌✌

Answered by Anonymous
3
Given that (2m,m-1) is a solution of 2x+3y-9=0

It means that here value of x is 2m and value y is m-1.

So, we can put these values of x and y in 2x+3y-9=0

we get --

2(2m)+3(m-1)-9 = 0

2 × 2m + 3(m-1) - 9 = 0

Multiply (m-1) with 3

2 × 2m + 3m - 3 - 9 = 0

4m + 3m - 3 - 9 = 0

collect like terms

7m - 12 = 0

7m = 12

m \:  =  \frac{12}{7}

or m = 1.71
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