(2m),(m-1) is a solution of 2x+3y-9=0, find the value of m
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Answered by
2
Answer:
Step-by-step explanation:
Let x=2m
And y=m-1
So
2x+3y-9=0
2x+3y=9
2×2m+3×(m-1)=9
4m+3m-3=9
7m=9+3
7m=12
m=12/7
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Answered by
3
Given that (2m,m-1) is a solution of 2x+3y-9=0
It means that here value of x is 2m and value y is m-1.
So, we can put these values of x and y in 2x+3y-9=0
we get --
2(2m)+3(m-1)-9 = 0
2 × 2m + 3(m-1) - 9 = 0
Multiply (m-1) with 3
2 × 2m + 3m - 3 - 9 = 0
4m + 3m - 3 - 9 = 0
collect like terms
7m - 12 = 0
7m = 12
or m = 1.71
It means that here value of x is 2m and value y is m-1.
So, we can put these values of x and y in 2x+3y-9=0
we get --
2(2m)+3(m-1)-9 = 0
2 × 2m + 3(m-1) - 9 = 0
Multiply (m-1) with 3
2 × 2m + 3m - 3 - 9 = 0
4m + 3m - 3 - 9 = 0
collect like terms
7m - 12 = 0
7m = 12
or m = 1.71
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