Question

2M of 100 ml Na2 SO4 is mixed with 3M of 100 ml NaCl solution and 1M of 200 ml CaCl2 solution. Then the ratio of the concentration of cation and anion. ​

Answer 1

Answer:

Explanation:

First work out any terms within brackets by multiplying them out;

= 2 + 2x [6x + 4 +2] = 2 + 2x [6x + 6]

Now eliminate the parentheses by multiplying any number outside it;

Answer 2

Answer:

Correct option is

D

1

mole=

V(in ml)

M×1000

Na

2

SO

4

→2Na

+

+SO

4

2−

0.2 0 0

0.4 0.2

[Na

+

]=(0.4/100)×1000=4M

[SO

4

2−

]=(0.2/100)×1000=2M

NaCl→Na

+

+Cl

−

0.3 0 0

0.3 0.3

[Na

+

]=[Cl

−

]=(0.3/100)×1000=3M

CaCl

2

→Ca

2+

+2Cl

−

0.2 0 0

0.2 0.4

[Ca

2+

]=(0.2/100)×1000=2M

[Cl

−

]=(0.4/100)×1000=4M

Ratio of concentration of cation and anion =

2+3+4

4+3+2

=1