Question

2M of100 ml Na2So4 is mixed with 3M of 100ml NaCl solution and 1M of 200 ml cacl2 solution then the ratio of contiontration of cation and anion is​

Answer 1

answer :- 1 : 1

explanation :- for 2M of 100ml Na2SO4

number of mole of solution = 2M × 100/1000 = 0.2

so, mole of cations = 2 × 0.2 = 0.4[ as 2 atom of Na in Na2SO4 ]

mole of anions = 0.2

for 3M of 100ml NaCl solution,

number of mole of solution =3M × 100/1000 = 0.3

so, mole of cations = 0.3

and mole of anions = 0.3

for 1M of 200ml CaCl2 solution,

number of mole of solution = 1M × 200/1000 = 0.2

so, mole of cations = 0.2

mole of anions = 2 × 0.2 = 0.4

now, total number of mole of cations = 0.4 + 0.3 + 0.2 = 0.9

so, concentration of cations = 0.9mole × 1000 /(100 + 100 + 200)ml = 2.25M

again, total number of mole of anions = 0.2 + 0.3 + 0.4 = 0.9

so, concentration of anions = 0.9mole × 1000/(100 + 100+ 200)ml = 2.25M

so, ratio of concentration of cations and anions = 2.25 : 2.25 = 1 : 1

Answer 2

Explanation:

so the ratio comes to be 1:1

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