Question

2m upon n+n upon 2m ³​

Answer 1

Answer:

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Step-by-step explanation:

Now,

6m+1×10n+3×15m2m+3×32m−n×5m+n+3×6n+1 

=(2m+1×3m+1)×(2n+3×5n+3)×(3m×5m)2m+3×32m−n×5m+n+3×(2n+1×3n+1) 

=2m+n+4×32m+1×5mm+n+32m+n+4×32m+1×5m+n+3 

=1.