Question

(2m2+3n2)2 find by using identity 1​

Answer 1

$\left(2m^2+3n^2\right)^2$

$\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2$

$a=2m^2,\:\:b=3n^2$

$=\left(2m^2\right)^2+2\cdot \:2m^2\cdot \:3n^2+\left(3n^2\right)^2$

$=4m^4+12m^2n^2+9n^4$

Answer 2

Answer:

$\huge\underbrace\mathcal\purple{Answer:-}$

$(2 {m}^{2} + 3 {n}^{2} )^{2}$

$solution \: \\ 4 {m}^{2} + 12 {m}^{2} {n}^{2} + 9 {n}^{4}$

The above attachment is your answer.

Step-by-step explanation:

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