-2m2no,m+3n,m2n+n2-2mn,4m,-12mno
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Answer:
(A) Cr
2+
is a reducing agent. It itself loses electrons (and hence acts as a reducing agent) and forms higher oxidation states. In fact, +6 oxidation state of Cr is very stable.
Hence, the option (A) is correct.
(B) Mn
3+
is an oxidizing agent. It itself gains electrons (and hence acts as an oxidizing agent) to form Mn
2+
with 3d
5
electronic configuration which is stable as it is half-filled.
Hence, the option (B) is correct.
(C) Cr and Mn have outer ionic configurations of 3d
5
4s
1
and 3d
5
4s
2
respectively.
Hence, both Cr
2+
and Mn
3+
exhibit d
4
electronic configuration.
Hence, the option (C) is correct.
(D) When Cr
2+
is used as a reducing agent, the chromium ion attains d
3
(as in Cr
3+
) electronic configuration.
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