Math, asked by ashi7102, 3 days ago

-2m2no,m+3n,m2n+n2-2mn,4m,-12mno

Answers

Answered by Ajaysunil2003
0

Answer:

(A) Cr

2+

is a reducing agent. It itself loses electrons (and hence acts as a reducing agent) and forms higher oxidation states. In fact, +6 oxidation state of Cr is very stable.

Hence, the option (A) is correct.

(B) Mn

3+

is an oxidizing agent. It itself gains electrons (and hence acts as an oxidizing agent) to form Mn

2+

with 3d

5

electronic configuration which is stable as it is half-filled.

Hence, the option (B) is correct.

(C) Cr and Mn have outer ionic configurations of 3d

5

4s

1

and 3d

5

4s

2

respectively.

Hence, both Cr

2+

and Mn

3+

exhibit d

4

electronic configuration.

Hence, the option (C) is correct.

(D) When Cr

2+

is used as a reducing agent, the chromium ion attains d

3

(as in Cr

3+

) electronic configuration.

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