Question

(2m³+m²+m+9)÷(2m-1 divide and write the quotient and the remainder

Answer 1

Step-by-step explanation:

hope these can be help you

Answer 2

The quotient of division is $\bf \red{{m}^{2} + m + 1}$ and remainder is 10.

Given:

• $(2 {m}^{3} + {m}^{2} + m + 9) \div (2m - 1)$

To find:

• Divide and write quotient and remainder.

Solution:

Perform long division.

While performing division of polynomials, just focus on the first terms of both divisor and dividend.

$2m - 1 \: ) \: 2 {m}^{3} + {m}^{2} + m + 9 \: ( {m}^{2} + m + 1 \\ 2 {m}^{3} - {m}^{2} \: \: \: \: \: \:\: \:\: \: \: \: \:\: \: \: \: \: \:\: \: \: \: \\ ( - ) \: \: \: ( + ) \: \:\quad \: \: \: \: \: \: \: \: \: \: \: \:\: \: \: \: \\ - - - - - - \: \: \: \: \: \: \\ 2 {m}^{2} + m \\ 2 {m}^{2} - m \\ ( - ) \: \: ( + ) \\ - - - - - - \\ 2m + 9 \\ 2m - 1 \\ ( - ) \: \: ( + ) \\ - - - - - - \\ 10 \\ - - - - - -$

Thus,

Quotient of division is $\bf {m}^{2} + m + 1$ and remainder is 10.

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