2mg+o2=2mgo/calculate how much oxygen is required to combust 10 moles of magnesium from the given equation
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Hello dear,
◆ Answer-
Amount of O2 required = 160 g
◆ Explaination-
# Given-
n(Mg) = 10 mol
# Solution-
According to reaction,
2Mg + O2 ---> 2MgO
To combust 2 mol of Mg, 1 mol of O2 is required.
Thus, to burn 10 mol of Mg, 5 mol of O2 is required.
Amount of O2 required,
Weight = Molecular mass × no of moles
Weight = 32 × 5
Weight = 160 g
Therefore, 160 g of O2 is required to burn 10 moles of magnesium.
Hope this helps you...
◆ Answer-
Amount of O2 required = 160 g
◆ Explaination-
# Given-
n(Mg) = 10 mol
# Solution-
According to reaction,
2Mg + O2 ---> 2MgO
To combust 2 mol of Mg, 1 mol of O2 is required.
Thus, to burn 10 mol of Mg, 5 mol of O2 is required.
Amount of O2 required,
Weight = Molecular mass × no of moles
Weight = 32 × 5
Weight = 160 g
Therefore, 160 g of O2 is required to burn 10 moles of magnesium.
Hope this helps you...
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