Question

2MG + O2gives 2mgo what is the total number of molecules taking part in above reaction what is number of molecules of reactant taking part in above reaction how many products are formed in above reaction

Answer 1

in the reaction 2Mg(s) + O2(g) → 2MgO(s)

the mole ratio of Mg : O2 : MgO

is 2 : 1 : 2

That is, the complete reaction requires twice as many moles of magnesium as there are moles of oxygen.

n moles of oxygen gas will react with (2 × n) moles of magnesium to produce (2 × n) moles of magnesium oxide.

in the reaction 2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

the mole ratio of Al(OH)3 : H2SO4 : Al2(SO4)3 : H2O

is 2 : 3 : 1 : 6

For each mole of Al2(SO4)3 produced, twice as many moles of Al(OH)3 are required to react with three times as many moles of H2SO4.

n moles of Al2(SO4)3 are produced when (2 × n) moles of Al(OH)3 react with (3 × n) moles of H2SO4. (6 × n) moles of H2O will also be produced.

Answer 2

hlo mate..

there are total 4 moles taking part (2moles of Mg and 2 moles of O.)
and giving 2 moles of MgO


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i hope it is helpful to you....