Math, asked by gousheyabegumgoushey, 10 hours ago

2mn sino=m²n²x coso find

Answers

Answered by dimpaljatin1886

0

Answer:

2mn sino = (m²-n²) coso

temo = m²-n²/2mn = sino

√m²-n² + ( 2mn )² / m² - n²

m²+n²/m²-n²

coso = m²-n²/m²+n²

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