Question

2mx²-2(1+2m)x+(3+2m) solve by quadratic formula for real and distinct roots..​

Answer 1

Answer:

Answer:

m=1/2

Step-by-step explanation:

According to bx^{2} -4ac

=[-2(1+2m)]^{2} -4*2m*(3+2m)=0

=4(1+2m{2} )-8m(3+2m)=0

=4(1+4m+4m^{2} )-24m-16m^{2} =0

=4-8m=0

=1-2m=0

m=1/2

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Answer 2

Answer:

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