2n-13/5-n-9/5=1+n-3/11
Answers
Step-by-step explanation:
Going through the different answers given below, there are so many logics but too deep.
I have another logic, which is somewhat simple what i thought, and feel its feasible.
if 3+2=7 then one of the ways it could have come to this conclusion is, (3*2)+1=7. Though it shows the symbol as addition, as it is a comparitive puzzle i am taking in this way. Now it follows like this.
3+2=7 means (3*2)+1=7
5+4=23 means (5*4)+3=23
7+6=47 means (7*6)+5=47
9+8=79 means (9*8)+7=79
Now comes the tricky part. If you can see after multiplying the digits, which were given supposedly for addition, and adding 1,3,5,7 subsequently to each of them the resultant of them was 7,23,47,79.
Now, though it may seem like they are adding sequential odd numbers, ut they can be prime numbers too.
Answer:
Please mark me brainy and Thanks please on me.
Step-by-step explanation:
Mathematics Part I Solutions Solutions for Class 10 Math Chapter 3 Arithmetic Progression are provided here with simple step-by-step explanations. These solutions for Arithmetic ular among Class 10 students for Math Arithmetic Progression Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Mathematics Part I Solutions Book of Class 10 Math Chapter 3 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Mathematics Part I Solutions Solutions. All Mathematics Part I Solutions Solutions for class Class 10 Math are prepared by experts and are 100% accurate.Page No 61:
Question 1:
Which of the following sequences are A.P. ? If they are A.P. find the common difference .
(1) 2, 4, 6, 8,....
(2) 2,
5
2
, 3,
7
3
,....
(3) –10, –6, –2, 2...
(4) 0.3, 0.33, 0.333,...
(5) 0, –4, –8, –2) 2,
5
2
, 3,
7
3
,....
(3) –10, –6, –2, 2...
(4) 0.3, 0.33, 0.333,...
(5) 0, –4, –8, –12,...
(6) -
1
5
,-
1
5
,-
1
5
,...
(7) 3, 3+
√
2
, 3+2
√
2
, 3+3
√
2
(8) 127, 132, 137,...
ANSWER:
(1) 2, 4, 6, 8,....
The given sequence is an A.P.
Common difference = Second term − First term
= 4 − 2
= 2
(2) 2,
5
2
, 3,
7
3
,....
The given sequence is not an A.P.
The given sequence is not an A.P.
(3) –10, –6, –2, 2...
The given sequence is an A.P.
Common difference = Second term − First term
= (−6) − (−10)
= 4
(4) 0.3, 0.33, 0.333,...
The given sequence is not an A.P.
(5) 0, –4, –8, –12,...
The given sequence is an A.P.
Common difference = Second term − First term
= (−4) − (0)
= −46) -
1
5
,-
1
5
,-
1
5
,...
The given sequence is an A.P.
Common difference = Second term − First term
= (−
1
5
) − (−
1
5
)
= 0
(7) 3, 3+
√
2
, 3+2
√
2
, 3+3
√
2
The given sequence is an A.P.
Common difference = Second term − First term
= 3+
√
2
-3
=
√
2
(8) 127, 132, 137,...
The given sequence is an A.P.
Common difference = Second term − First term
= (132)