2n=16 is in a primary spermatocyte which is in metaphase of first meiotic division. What shal be the total number of chromatids in each of the secondary spermatocyte?
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So, if there are 16 chromosomes in primary spermatocyte, the secondary spermatocyte will have half the number i.e.; 8 chromsomes and the chromatids will be 8*2 = 16.
Thus, the correct answer is '16'.
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