Question

(2n +2)!/(2n)! plesase answer this question​

Answer 1

Step-by-step explanation:

(2n+2)!/2n!

(2n+2)! × (2n+1)!× 2n!/2n!

(2n+2)! × (2n+1)!

Answer 2

Answer:

(2n+2)!/2n! = (2n+2)(2n+1)(2n)!/2n!

= (2n+2)(2n+1)

= 4n^2 + 2n + 4n + 2

= 4n^2 + 6n + 2

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