2n^2 - n - 2415
Factorise it please
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Answered by
5
Given Equation is 2n^2 - n - 2415
= > 2n^2 + 69n - 70n - 2415
= > n(2n + 69) - 35(2n + 69)
= > (2n + 69)(n - 35)
Hope this helps!
= > 2n^2 + 69n - 70n - 2415
= > n(2n + 69) - 35(2n + 69)
= > (2n + 69)(n - 35)
Hope this helps!
siddhartharao77:
Gud luck!
Thank u ...i couldn't find the factors :p
Welcome
Answered by
2
Hey there !!
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2n² – n – 2415 = 0
2n² – 70n + 69n – 2415 = 0
2n ( n – 35 ) + 69 ( n – 35 ) = 0
( 2n + 69 ) ( n – 35 ) = 0
( 2n + 69 ) = 0 or ( n – 35 ) = 0
n = –69 / 2 or n = 35
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2n² – n – 2415 = 0
2n² – 70n + 69n – 2415 = 0
2n ( n – 35 ) + 69 ( n – 35 ) = 0
( 2n + 69 ) ( n – 35 ) = 0
( 2n + 69 ) = 0 or ( n – 35 ) = 0
n = –69 / 2 or n = 35
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Tq
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