Question

(2n 3 + 20n 2 + n) ÷ 10n 2
plz help​

Answer 1

Answer:

(2n³+20n²+n) ÷10n² $=\frac{2n^{2}+20n+1 }{10n}$

Step-by-step explanation:

Given that (2n³+20n²+n) ÷10n²

we have to find a solution of the above expression

(2n³+20n²+n) ÷10n²

$(2n^{3} +20n^{2} +n)/10n^{2} = \frac{2n^{3}+20n^{2}+n }{10n^{2} } =n(\frac{2n^{2}+20n+1 }{10n^{2} })$ $=\frac{2n^{2}+20n+1 }{10n}$

Multiply the coefficient of the first term by the constant = 2 × 1 = 2

Find two factors of 2 whose sum equals the coefficient of the middle term that is 20.

No factors are found.

Trinomial can not be factored.