2N 30 ml h2so4 is passed with nh3 and normality of h2so4 becomes .2N what volime og nh3 at stp is passed throigh h2so4
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Meq of original H2SO4=30×1=30H2SO4=30×1=30
Meq of H2SO4H2SO4 after passing NH3=30×0.2=6NH3=30×0.2=6
Meq of H2SO4H2SO4 lost =30−6=2430−6=24
Meq of NH3NH3 passed=Meq of H2SO4H2SO4 lost
w17w17×1000=24×1000=24
WNH3WNH3=0.408g
∴∴ Volume of NH3NH3 at STP=22.4×0.4081722.4×0.40817
⇒0.5376l⇒0.5376l
⇒537.6ml⇒537.6ml
Hence (a) is the correct answer.
Meq of original H2SO4=30×1=30H2SO4=30×1=30
Meq of H2SO4H2SO4 after passing NH3=30×0.2=6NH3=30×0.2=6
Meq of H2SO4H2SO4 lost =30−6=2430−6=24
Meq of NH3NH3 passed=Meq of H2SO4H2SO4 lost
w17w17×1000=24×1000=24
WNH3WNH3=0.408g
∴∴ Volume of NH3NH3 at STP=22.4×0.4081722.4×0.40817
⇒0.5376l⇒0.5376l
⇒537.6ml⇒537.6ml
Hence (a) is the correct answer.
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