(2n+3y-4z)sq
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Answer:
4n² + 9y² + 16z² + 12ny - 24yz - 16zn
Step-by-step explanation:
Using (a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca
(2n+3y-4z)^2 =2n^2+3y^2+(-4z)+2(2n+
=> (2n)² + (3y)² + ( - 4z)² + 2[ (2n)*(3y) + (3y)*(- 4z) + (- 4z)*(2n)]
=> 4n² + 9y² + 16z² + 2(6ny - 12yz - 8zn)
=> 4n² + 9y² + 16z² + 12ny - 24yz - 16zn
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